/opt/alt/python33/lib64/python3.3/lib-dynload
Edit: /opt/alt/python33/lib64/python3.3/lib-dynload/_heapq.cpython-33m.so (18864B)
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~ __gmon_start__ _init _fini __cxa_finalize _Jv_RegisterClasses PyInit__heapq PyModule_Create2 PyUnicode_DecodeUTF8 PyModule_AddObject PyObject_RichCompareBool PyExc_IndexError PyErr_SetString PyArg_ParseTuple PyObject_GetIter PyList_New PyIter_Next PyList_Append PyErr_Occurred PyList_Sort PyExc_RuntimeError _Py_NoneStruct PyExc_TypeError PyList_Reverse PyArg_UnpackTuple PyList_SetSlice libpython3.3m.so.1.0 libpthread.so.0 libc.so.6 _edata __bss_start _end /opt/alt/python33/lib64:/opt/alt/sqlite/usr/lib64:/opt/alt/openssl11/lib64 GLIBC_2.2.5 ui ! ! @ @ 7 @ @ @ @ @ @ < A w A P A `< A (A 8A @= @A k HA ` XA = `A hA @ xA `? A b A A ? A 8 A A @ # # # # # # # $ $ $ $ $ ($
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H5j H8jH([]A\A]A^A_f D HWHD$R0HD$Kf. HMHH<H HHH t1H\$HLH H([]A\A]A^A_tHCHP0eHOHD$HT$Q0HMHT$HD$H\$HHHHBHCHP03 D H H5 H8ffff. UHSHHF tSHFHH?HH HHt HyHS H H[] H1[]H H5 H81ffff. H\$Hl$HLd$Ll$H8HL$H5h 1H/u#1HHl$ H\$Ld$(Ll$0H8 D H|$.HHt1HH H$H E1H$IL9 HHI HHt#I$HHI$uID$LP0 D I$HHI$uID$LP0 @ HE HHHE K HHHHHHCH1P0f D HuH>tHtHE HHHE HEHP0 H{ tII?II f. LH4Iyf D HCL(HQHIU1HLu#I$HHI$uID$LP0 D HCH8L HHHHt&1Hu HEHP0HGP0ffffff. SHH5 1 HLD$IxtLHD$HP tJHx HPH$1H HHH|$it None. Push item onto heap, maintaining the heap invariant. heappushpop(heap, item) -> value. Push item on the heap, then pop and return the smallest item
from the heap. The combined action runs more efficiently than
heappush() followed by a separate call to heappop(). Pop the smallest item off the heap, maintaining the heap invariant. heapreplace(heap, item) -> value. Pop and return the current smallest value, and add the new item.
This is more efficient than heappop() followed by heappush(), and can be
more appropriate when using a fixed-size heap. Note that the value
returned may be larger than item! That constrains reasonable uses of
this routine unless written as part of a conditional replacement:
if item > heap[0]:
item = heapreplace(heap, item)
Transform list into a heap, in-place, in O(len(heap)) time. Find the n largest elements in a dataset.
Equivalent to: sorted(iterable, reverse=True)[:n]
Find the n smallest elements in a dataset.
Equivalent to: sorted(iterable)[:n]
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